A) 1672 years
B) 2391 years
C) 3291 years
D) 4453 years
Correct Answer: B
Solution :
[b] Given, for \[^{14}C\] \[{{A}_{0}}=16\,\,dis\,\,{{\min }^{-1}}{{g}^{-1}}\] \[A=12\,\,dis\,\,{{\min }^{-1}}{{g}^{-1}}\] \[{{t}_{1/2}}=5760\,\,years\] Now, \[\lambda =\frac{0.693}{{{t}_{1/2}}}=\frac{0.693}{5760}\] per year Then, from, \[t=\frac{2.303}{\lambda }{{\log }_{10}}\frac{{{A}_{0}}}{A}\] \[=\frac{2.303\times 5760}{0.693}{{\log }_{10}}\frac{16}{12}\approx 2391\]yearsYou need to login to perform this action.
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