A) 4.8
B) 3.6
C) 2.4
D) 1.2
Correct Answer: A
Solution :
[a] Nuclear radius, \[r\propto {{A}^{1/3}}\] where A is mass number \[\frac{{{r}_{Cu}}}{{{r}_{Al}}}={{\left( \frac{{{A}_{Cu}}}{{{A}_{Al}}} \right)}^{1/3}}={{\left( \frac{64}{27} \right)}^{1/3}}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,{{r}_{Cu}}=3.6\left( \frac{4}{3} \right)=4.8\,\,\,Fermi\]You need to login to perform this action.
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