A) 2.13 MeV
B) 0.13 MeV
C) 10 MeV
D) 12.13 MeV
Correct Answer: D
Solution :
[d] \[M{{(}_{8}}{{O}^{16}})=M{{(}_{7}}{{N}^{15}})+1{{m}_{P}}\] binding energy of last proton \[=M({{N}^{15}})+{{m}_{P}}-M{{(}_{1}}{{O}^{16}})\] \[=15.00011+1.00783-15.99492\] \[=0.01302\text{ }amu=12.13\text{ }MeV\]You need to login to perform this action.
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