A) 2
B) 3
C) 4
D) 5
Correct Answer: A
Solution :
[a] \[\frac{{{N}_{1}}}{{{N}_{2}}}={{e}^{\left( {{\lambda }_{2}}-{{\lambda }_{1}} \right)}}=\frac{1}{e}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,t=\frac{1}{{{\lambda }_{2}}-{{\lambda }_{1}}}=2\]You need to login to perform this action.
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