A) 2 : 3
B) 3 : 2
C) e : 1
D) (e-1) : 1
Correct Answer: B
Solution :
[b] \[{{N}_{1}}{{\lambda }_{1}}={{N}_{2}}{{\lambda }_{2}}\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{2}{3}\Rightarrow \frac{{{N}_{2}}}{{{N}_{1}}}=\frac{2}{3}\] \[\Rightarrow \] ratio of no. of nuclei of X to that of \[Y=3/2\]You need to login to perform this action.
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