A) 1
B) In 2
C) In (4/3)
D) 2 to (4/3)
Correct Answer: D
Solution :
[d] \[\frac{dN}{dt}=50-\frac{N}{0.5}\,\,\,\,\,\,\,\,\,\int\limits_{0}^{N}{\frac{dN}{50-2N}}=\int\limits_{0}^{t}{dt}\] \[N=(100(1-{{e}^{-t/2)}})=25\] \[t=2\] In \[(4/3)\]You need to login to perform this action.
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