A) \[C{{H}_{3}}-\overset{OD}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}\]
B) \[C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,=C{{D}_{3}}\]
C) \[C{{H}_{2}}=\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,-C{{H}_{2}}D\]
D) \[C{{D}_{2}}=\overset{OD}{\mathop{\overset{|}{\mathop{C}}\,}}\,-C{{D}_{3}}\]
Correct Answer: A
Solution :
[a] The enol form of acetone is \[C{{H}_{3}}-\overset{OH}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}\] with \[{{D}_{2}}O\] it gives \[C{{H}_{3}}-\overset{OD}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}\]You need to login to perform this action.
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