A) Carbanion
B) Carbene
C) Free radical
D) Carbocation
Correct Answer: D
Solution :
[d] \[SbC{{l}_{5}}\] pulls \[C{{l}^{-}}\]to form \[SbCl_{6}^{-}\] leaving behind planar \[{{C}_{6}}{{H}_{5}}-\overset{+}{\mathop{C}}\,H-C{{H}_{3}}\] carbonium ion. It can be attacked from either side leading to racemic mixture.You need to login to perform this action.
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