A) at the mean position of the platform
B) for an amplitude of \[\frac{g}{{{\omega }^{2}}}\]
C) for an amplitude of\[\frac{g}{{{\omega }^{2}}}\]
D) at the highest position of the platform
Correct Answer: B
Solution :
[b] For block A to move in S.H.M. \[mg-N=m{{\omega }^{2}}x\] where x is the distance from mean position For block to leave contact N = 0 \[\Rightarrow \,mg=m{{\omega }^{2}}x\Rightarrow x=\frac{g}{{{w}^{2}}}\]You need to login to perform this action.
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