A) 10J
B) 14J
C) 18J
D) 4J
Correct Answer: C
Solution :
[c] \[{{E}_{1}}=\frac{1}{2}k{{x}^{2}},\,{{E}_{2}}=\frac{1}{2}k{{y}^{2}},\] \[E=\frac{1}{2}k{{(x+y)}^{2}}=\frac{1}{2}k{{x}^{2}}+\frac{1}{2}k{{y}^{2}}+kxy\] \[={{E}_{1}}+{{E}_{2}}+2\sqrt{{{E}_{1}}{{E}_{2}}}=2+8+2\sqrt{16}=18J\]You need to login to perform this action.
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