A) \[2\pi \sqrt{\frac{m}{\alpha }}\]
B) \[2\pi \sqrt{\frac{m}{2\alpha }}\]
C) \[\pi \sqrt{\frac{2m}{\alpha }}\]
D) \[2\pi \sqrt{\frac{m}{{{\alpha }^{2}}}}\]
Correct Answer: B
Solution :
[b] \[U={{U}_{0}}+\alpha {{x}^{2}}\Rightarrow F=-\frac{DU}{dx}=-2\alpha x\] \[a=\frac{F}{m}=-\frac{2\alpha }{m}x\] \[\Rightarrow \,\,{{\omega }^{2}}=\frac{2\alpha }{m}\Rightarrow T=\frac{2\pi }{\omega }\Rightarrow T=\frac{2\pi }{\omega }=2\pi \sqrt{\frac{m}{2\alpha }}\]You need to login to perform this action.
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