A) \[\pi \sqrt{2}\sec \]
B) \[\frac{\pi }{10}\sqrt{2}\sec \]
C) \[\frac{\pi }{10\sqrt{2}}\sec \]
D) \[\frac{5\pi }{\sqrt{2}}\sec \]
Correct Answer: B
Solution :
[b] Given, \[V=36\times \frac{5}{18}m/s=10/s\], \[g=10m/{{s}^{2}},\,r=10m,\,l=1m\] \[T=2\pi \sqrt{\frac{\ell }{{{g}^{2}}+{{\left( \frac{{{v}^{2}}}{r} \right)}^{2}}}}=2\pi \sqrt{\frac{1}{{{10}^{2}}+{{\left( \frac{100}{10} \right)}^{2}}}}\] \[=\frac{\pi }{10}\sqrt{2}\sec \]
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