A) 144\[{{\pi }^{2}}\]
B) 188 \[{{\pi }^{2}}\]
C) 288\[{{\pi }^{2}}\]
D) None of these
Correct Answer: C
Solution :
[c] \[Max.\text{ }force\text{ }=\text{ }mass\text{ }\times \text{ }max.\text{ }acceleration\] \[=m\,4\,{{\pi }^{2}}{{v}^{2}}a=1\times 4\times {{\pi }^{2}}{{(60)}^{2}}\times 0.02\] \[=288{{\pi }^{2}}\]
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