A) \[\frac{\sqrt{2}A}{3}\]
B) \[\frac{\sqrt{3}A}{2}\]
C) \[\frac{2A}{\sqrt{3}}\]
D) \[\frac{3A}{\sqrt{2}}\]
Correct Answer: B
Solution :
[b] \[v=\omega {{[{{A}^{2}}-{{x}^{2}}]}^{1/2}}\Rightarrow x={{\left[ {{A}^{2}}-\frac{{{V}^{2}}}{{{\omega }^{2}}} \right]}^{1/2}}\] Given that \[v=\frac{{{v}_{\max }}}{2}=\frac{A\omega }{2}\]. \[so,{{\left[ {{A}^{2}}-\frac{{{A}^{2}}{{\omega }^{2}}}{4{{\omega }^{2}}} \right]}^{1/2}}=\frac{\sqrt{3}}{2}.A\]
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