A) 5 cm
B) 7.5 cm
C) 10 cm
D) 12.5 cm
Correct Answer: A
Solution :
[a] Velocity in SHM is given by \[v=\omega \sqrt{{{a}^{2}}-{{y}^{2}}}\] At \[y=4cm=0.04m,\,v=3m/s\] \[\therefore \,\,3=\omega \sqrt{{{a}^{2}}-{{(0.04)}^{2}}}\] ?. (i) At \[y=3cm=0.03m,\,v=4m/s\] \[\therefore \,\,4=\omega \sqrt{{{a}^{2}}-{{(0.03)}^{2}}}\] ?. (ii) Dividing (2) by (1), we get a =0.05=5cm
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