A)
B)
C)
D)
Correct Answer: D
Solution :
[d] \[{{v}^{2}}={{\omega }^{2}}({{A}^{2}}-{{x}^{2}})\] ...(i) and \[{{a}^{2}}=({{\omega }^{2}}{{x}^{2}}){{\omega }^{4}}{{x}^{2}}\] ...(ii) From above equations, we have \[{{v}^{2}}=-\frac{{{a}^{2}}}{{{\omega }^{2}}}+{{\omega }^{2}}{{A}^{2}}\Rightarrow y=mx+c\] It represents straight line with negative slope.
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