question_answer

A point mass oscillates along the x-axis according to the law\[x={{x}_{0}}\cos (\omega t-\pi /4)\]. If the acceleration of the particle is written as \[a=A\,\cos (\omega t+\delta )\], then

A) \[A={{x}_{0}}{{\omega }^{2}},\,\delta =3\pi /4\]        

B) \[A={{x}_{0}},\,\delta =-\pi /4\]

C) \[A={{x}_{0}}{{\omega }^{2}},\,\delta =\pi /4\]          

D) \[A={{x}_{0}}{{\omega }^{2}},\,\delta =-\pi /4\]