JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Oscillations

  • question_answer
    A particle of mass 10 gm is describing S.H. M. along a straight line with period of 2 sec and amplitude of 10 cm. Its kinetic energy when it is at 5 cm from its equilibrium position is

    A) \[37.5{{\pi }^{2}}\,ergs\]

    B) \[3.75{{\pi }^{2}}\,ergs\]

    C) \[375{{\pi }^{2}}\,ergs\]

    D) \[0.375{{\pi }^{2}}\,erg\]

    Correct Answer: C

    Solution :

    [c] Kinetic energy \[K=\frac{1}{2}m{{\omega }^{2}}({{a}^{2}}-{{y}^{2}})\] \[=\frac{1}{2}\times 10\times {{\left( \frac{2\pi }{2} \right)}^{2}}[{{10}^{2}}-{{5}^{2}}]=375{{\pi }^{2}}ergs\]


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