A) \[t={{t}_{0}}\]
B) \[t={{t}_{0}}/2\]
C) \[t=2{{t}_{0}}\]
D) \[t=4{{t}_{0}}\]
Correct Answer: C
Solution :
[c] \[{{t}_{0}}=2\pi \sqrt{\frac{\ell }{g}}\]. The restoring force in a liquid \[F=-(mg-V{{\rho }_{e}}g)\sin \theta \] \[=-\,\left( mg-\frac{m}{\left( \frac{4}{3}\times 1000 \right)}\times 1000g \right)\left( \frac{x}{\ell } \right)\] \[or\,\,\,a=\left( g-\frac{3g}{4} \right)\left( \frac{-x}{\ell } \right)=\frac{g}{4}\left( \frac{-x}{\ell } \right)\] \[\therefore \,\,t=2\pi \sqrt{\frac{\ell }{(g/4)}}=2{{t}_{0}}\].You need to login to perform this action.
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