JEE Main & Advanced
Physics
Wave Mechanics
Question Bank
Self Evaluation Test - Oscillations
question_answer
A particle performs SHM in a straight line. In the first second, starting from rest, it travels a distance a and in the next second it travels a distance b in the same direction. The amplitude of the SHM is
A)\[a-b\]
B)\[\frac{2a-b}{3}\]
C)\[\frac{2{{a}^{2}}}{3a-b}\]
D)None of these
Correct Answer:
C
Solution :
[c] When particle starts from mean position, \[x=A\,\cos \,\omega t\] \[\therefore \,\,\,(A-a)=A\,\cos (\omega \times 1)\] Or \[(A-a)=A\,cos\,\omega \] ?..(i) \[Also\,\,\,A-(a+b)=A\,\cos (\omega \times 2)\] Or \[A-(a+b)=A\,\cos \,2\omega \] ??(ii) After simplifying above equations, we get \[A=\left[ \frac{2{{a}^{2}}}{3a-b} \right]\]