JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Oscillations

  • question_answer
    A simple harmonic motion has an amplitude A and time period T. The time required by it to travel from x=A to x=A/2 is

    A) T/6

    B) T/4  

    C) T/3

    D) T/2

    Correct Answer: A

    Solution :

    [a] At extreme position \[y=A\,\sin (\omega t+\frac{\pi }{2})=A\cos \,\omega t\] Now \[y=A/2\,then\,A/2=A\,\cos \,\omega t\] \[\Rightarrow \,\,\omega t={{\cos }^{-1}}(1/2)\,\]     \[\frac{2\pi }{T}t=\frac{\pi }{3}\Rightarrow t=T/6\]


You need to login to perform this action.
You will be redirected in 3 sec spinner