question_answer

A simple pendulum has time period\[{{T}_{1}}\]. The point of suspension is now moved upward according to the relation \[y=K{{t}^{2}},(K=1m/{{s}^{2}})\] where y is the vertical displacement. The time period now becomes\[{{T}_{2}}\]. The ratio of \[\frac{T_{1}^{2}}{T_{2}^{2}}\] is \[(g=10m/{{s}^{2}})\]

A) 5/6 

B) 6/5   

C) 1

D) 4/5