2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Wave Mechanics

JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Oscillations

  • question_answer
    A particle of mass m is attached to a spring (of spring constant k) and has a natural angular frequency\[{{\omega }_{0}}\]. An external force F (t) proportional to \[\cos \,\omega t(\omega \ne {{\omega }_{0}})\] is applied to the oscillator. The displacement of the oscillator will be proportional to

    A) \[\frac{1}{m(\omega _{0}^{2}+{{\omega }^{2}})}\]

    B) \[\frac{1}{m(\omega _{0}^{2}-{{\omega }^{2}})}\]

    C) \[\frac{m}{\omega _{0}^{2}-{{\omega }^{2}}}\]

    D) \[\frac{m}{(\omega _{0}^{2}+{{\omega }^{2}})}\]

    Correct Answer: B

    Solution :

    [b] \[x=A\,\sin (\omega t+\phi )\] Where \[A=\frac{{{F}_{0}}}{m\sqrt{{{(\omega _{0}^{2}-{{\omega }^{2}})}^{2}}}}=\frac{{{F}_{0}}}{m(\omega _{0}^{2}-{{\omega }^{2}})}\] Here damping effect is considered to be zero \[\therefore \,x\propto \frac{1}{m({{\omega }_{0}}^{2}-{{\omega }^{2}})}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner