A) 4360
B) 5760
C) 5930
D) None of these
Correct Answer: B
Solution :
[b] First we have to select 2 men for bow side and 3 for stroke side. The number of selections of the crew for two sides \[{{=}^{5}}{{C}_{2}}{{\times }^{3}}{{C}_{3}}\] For each selection there are 4 persons on both sides. Who can be arranged in \[4!\times 4!\] ways? Required number of arrangement \[{{=}^{5}}{{C}_{2}}{{\times }^{3}}{{C}_{3}}\times 4!\times 4!=5760\]You need to login to perform this action.
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