A) 16
B) 36
C) 60
D) 180
Correct Answer: C
Solution :
[c] X-X-X-X-X. The four digits 3, 3, 5, 5, can be arranged at (-) places in \[\frac{4!}{2!2!}=6\] ways. The five digits 2, 2, 8, 8, 8, can be arranges at (x) place in \[\frac{5!}{2!3!}\] ways = 10 ways Total no. of arrangements \[=6\times 10=60\] waysYou need to login to perform this action.
You will be redirected in
3 sec