JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Self Evaluation Test - Permutations and Combinatioins

  • question_answer
    How many different nine digit numbers can be formed form the number 223355888 by rearranging its digits so that the odd digits occupy even positions?

    A) 16

    B) 36

    C) 60

    D) 180

    Correct Answer: C

    Solution :

    [c] X-X-X-X-X. The four digits 3, 3, 5, 5,  can be arranged at (-) places in \[\frac{4!}{2!2!}=6\] ways. The five digits 2, 2, 8, 8, 8, can be arranges at (x) place in \[\frac{5!}{2!3!}\] ways = 10 ways Total no. of arrangements \[=6\times 10=60\] ways

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