A) 90
B) 180
C) 91
D) 100
Correct Answer: C
Solution :
[c] We have \[A=\{2,3,5,7,11,13,17,19,23,29\}\] A contains 10 elements. So numerator and denominator each can be chosen in 10 ways. So no. of rational numbers \[=10\times 10-10+1=91\] (Out of these selections, 10 numbers are simply 1)You need to login to perform this action.
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