A) At least 500 but less than 750
B) At least 750 but less than 1000
C) At least 1000
D) Less than 500
Correct Answer: C
Solution :
[c] 4 novels, out of 6 novels and 1 dictionary out of 3 can be selected in \[^{6}{{C}_{4}}{{\times }^{3}}{{C}_{1}}\] ways Then 4 novels with one dictionary in middle can be arranged in 4! Ways. \[\therefore \] Total ways of arrangement \[{{=}^{6}}{{C}_{4}}{{\times }^{3}}{{C}_{1}}\times 4!=1080\]
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