JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Self Evaluation Test - Permutations and Combinatioins

  • question_answer
    The number of ways in which an examiner can assign 30 marks to 8 questions, giving not less than 2 marks to any question, is:

    A) \[^{30}{{C}_{7}}\]

    B) \[^{21}{{C}_{8}}\]

    C) \[^{21}{{C}_{7}}\]     

    D) \[^{30}{{C}_{8}}\]

    Correct Answer: C

    Solution :

    [c] 30 marks to be allotted to 8 questions. Each questions has to be given \[\ge 2\,\,marks\] Let questions be a, b, c, d, e, f, g, h and \[a+b+c+d+e+f+g+h=30\] Let \[a={{a}_{1}}+2\] so, \[{{a}_{1}}\ge 0,\] \[b={{a}_{2}}+2\,\,\,so,\,\,{{a}_{2}}\ge 0,....{{a}_{8}}\ge 0\] So, \[\left. \begin{matrix}    {{a}_{1}}+{{a}_{2}}+...+{{a}_{8}}  \\    +2+2+....+2  \\ \end{matrix} \right\}=30\] \[\Rightarrow \,\,\,\,{{a}_{1}}+{{a}_{2}}+...+{{a}_{8}}=30-16=14\] So, this is a problem of distributing 14 articles in 8 groups. Number of ways \[{{=}^{14+8-1}}{{C}_{8-1}}{{=}^{21}}{{C}_{7}}\]


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