JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Self Evaluation Test - Physical World, Units and Measurements

  • question_answer
    In a new system of units, the fundamental quantities mass, length and time are replaced by acceleration 'a', density \['\rho '\] and frequency\[f\]. The dimensional formula for force in this system is

    A) \[[\rho {{a}^{4}}f]\]

    B)  \[[\rho {{a}^{4}}{{f}^{-6}}]\]

    C)  \[[{{\rho }^{-1}}{{a}^{-4}}{{f}^{6}}]\]

    D)  \[[{{\rho }^{-1}}{{a}^{-4}}{{f}^{6}}]\]

    Correct Answer: B

    Solution :

    [b] \[F=ma=\rho \] volume ?a? To write volume in terms of ?a? and ?f? Volumes \[={{L}^{3}}{{\left( \frac{L}{{{T}^{2}}} \right)}^{3}}{{T}^{6}}={{a}^{3}}{{f}^{-6}}\] \[\therefore \,\,\,\,F=\rho {{a}^{4}}{{f}^{-6}}\]


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