A) Resistance
B) charge
C) Voltage
D) current
Correct Answer: D
Solution :
[d] Dimensionally \[{{\varepsilon }_{0}}L=C\] where C= capacitance Now the given expression reduces to \[C\Delta V/\Delta t.\] Dimensionally \[C\Delta V=q\] where q is charge. Again the given expression reduces to \[q/\Delta t.\] Dimensionally\[\frac{q}{\Delta t}=I\] where I is currentYou need to login to perform this action.
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