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JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Self Evaluation Test - Physical World, Units and Measurements

  • question_answer
    The current voltage relation of a diode is given by\[I=({{e}^{1000V/T}}-1)mA\], where the applied voltage V is in volts and the temperature T is in degree kelvin. If a student makes an error measuring \[\pm 0.01\text{ }V\]while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA?

    A) 0.2Ma

    B)  0.02mA

    C)  0.5mA

    D)  0.05mA  

    Correct Answer: A

    Solution :

    [a] The current voltage relation of diode is \[I=({{e}^{1000V/T}}-1)mA(given)\] When, \[I=5mA,{{e}^{1000V/T}}=6mA\] Also, \[dI=({{e}^{1000V/T}})\times \frac{1000}{T}\] (By exponential function) \[=(6mA)\times \frac{1000}{300}\times (0.01)=0.2mA\]


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