A) \[\frac{N-{{m}^{3}}}{{{x}^{3}}},V/{{m}^{2}},\,N/{{m}^{2}}-C\]
B) \[V-{{m}^{2}},V/m,\,N/{{m}^{2}}-C\]
C) \[V/{{m}^{2}},V/m,\,N-C/{{m}^{2}}\]
D) \[V/m,\,N-{{m}^{3}}/C,\,N-C/m\]
Correct Answer: A
Solution :
[a] Unit of Electric field \[(E)=(N/C)=(V/m)\] So, unit of \[A=E\times {{x}^{3}}=\frac{N-{{m}^{3}}}{C}=(V-{{m}^{2}})\] Unit of \[B=E/y=\frac{N}{mc}=\left( \frac{V}{{{m}^{2}}} \right)\] Unit of \[C=E/{{z}^{2}}=\frac{N}{{{m}^{2}}c}=\left( \frac{V}{{{m}^{3}}} \right)\]
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