A) 0.4
B) 40
C) 400
D) 0.04
Correct Answer: B
Solution :
[b] In CGS system, \[d=4\frac{g}{c{{m}^{3}}}\] The unit of mass is 1 00g and unit of length is 10 cm, so \[density=\frac{4\left( \frac{100g}{100} \right)}{{{\left( \frac{10}{10}cm \right)}^{3}}}=\frac{\left( \frac{4}{100} \right)}{{{\left( \frac{1}{10} \right)}^{3}}}\frac{(100g)}{{{(10cm)}^{3}}}\] \[=\frac{4}{100}\times {{(10)}^{3}}.\frac{100g}{{{(10cm)}^{3}}}=40unit\]
You need to login to perform this action.
You will be redirected in
3 sec
