A) \[1.9\times {{10}^{10}}\]
B) \[1.9\times {{10}^{11}}\]
C) \[1.9\times {{10}^{12}}\]
D) \[1.9\times {{10}^{13}}\]
Correct Answer: C
Solution :
[c] It is given that Young's modulus (Y) is, \[Y=1.9\times {{10}^{11}}N/{{m}^{2}}\] \[1N={{10}^{5}}dyne\] \[So,Y=1.9\times {{10}^{11}}\times {{10}^{5}}dyne/{{m}^{2}}\] Convert meter to centimeter \[\because 1m=100cm\] \[Y=1.9\times {{10}^{11}}\times {{10}^{5}}dyne/{{(100)}^{2}}c{{m}^{2}}\] \[=1.9\times {{10}^{12}}dyne/c{{m}^{2}}\]
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