A) \[k{{g}^{-1}}{{m}^{-1}}{{C}^{2}}\]
B) \[kgm{{C}^{-2}}\]
C) \[kg\,m{{s}^{-4}}{{C}^{-2}}\]
D) \[k{{g}^{-1}}{{s}^{-3}}{{C}^{-2}}\]
Correct Answer: B
Solution :
[b] We have, \[c=\frac{1}{\sqrt{{{\mu }_{0}}{{\in }_{0}}}}\Rightarrow {{\mu }_{0}}=\frac{1}{{{\in }_{0}}{{c}^{2}}}\] \[\therefore \] units of \[{{\mu }_{0}}=\frac{1}{units\,of\,{{\in }_{0}}{{c}^{2}}}\] \[=\frac{1}{{{N}^{-1}}{{C}^{2}}{{m}^{-2}}{{(m{{s}^{-1}})}^{2}}}=N{{s}^{2}}{{C}^{-2}}\] \[=(kgm{{s}^{-2}}){{s}^{2}}{{C}^{-2}}=kgm{{C}^{-2}}\]You need to login to perform this action.
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