JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Self Evaluation Test - Physical World, Units and Measurements

  • question_answer
    Which one of the following represents the correct dimensions of the coefficient of viscosity?

    A)  \[[M{{L}^{-1}}{{T}^{-1}}]\]

    B)  \[[ML{{T}^{-1}}]\]

    C)  \[[M{{L}^{-1}}{{T}^{-2}}]\]

    D)  \[[M{{L}^{-2}}{{T}^{-2}}]\]

    Correct Answer: A

    Solution :

    [a] From stokes law \[F=6\pi \eta rv\Rightarrow \eta =\frac{F}{6\pi rv}\] \[\therefore \,\,\eta =\frac{ML{{T}^{-2}}}{[L][L{{T}^{-1}}]}\Rightarrow \eta =[M{{L}^{-1}}{{T}^{-1}}]\]


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