A) \[[{{M}^{0}}{{L}^{0}}{{T}^{0}}]\]
B) \[[ML{{T}^{-2}}]\]
C) \[[M{{L}^{2}}{{T}^{-2}}]\]
D) \[[M{{L}^{0}}{{T}^{-3}}]\]
Correct Answer: D
Solution :
[d] Energy incident per unit area per second \[=\frac{Energy}{area\times \sec ond}=\frac{M{{L}^{2}}{{T}^{-2}}}{{{L}^{2}}T}=M{{T}^{-3}}\]
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