JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Self Evaluation Test - Physical World, Units and Measurements

  • question_answer
    Distance travelled by a particle at any instant ?t? can be represented as \[S=A(t+B)+C{{t}^{2}}\].The dimensions of B are

    A)        \[[{{M}^{0}}{{L}^{1}}{{T}^{-1}}]\]

    B)  \[[{{M}^{0}}{{L}^{0}}{{T}^{1}}]\]

    C)  \[[{{M}^{0}}{{L}^{-1}}{{T}^{-2}}]\]

    D)  \[[{{M}^{0}}{{L}^{2}}{{T}^{-2}}]\]

    Correct Answer: B

    Solution :

    [b] In \[S=A(t+B)+C{{t}^{2}};\]B is added to time Therefore, dimensions of B are those of time.


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