A) work/time
B) work x distance
C) work/distance
D) work x time
Correct Answer: B
Solution :
[b] From K \[=\frac{Bx}{{{x}^{2}}+{{A}^{2}}}=\frac{Bx}{{{x}^{2}}}=\frac{B}{x}\] \[\therefore \,\,\,B=K\times x=K.E.\times dis\tan ce\] \[=work\times dis\tan ce.\]
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