A) \[4\Omega \pm 16.25%\]
B) \[(4\pm 0.7)\Omega \]
C) \[4\Omega \pm 0.7%\]
D) \[4\Omega \pm 7%\]
Correct Answer: A
Solution :
[a] Actual \[R=\frac{8}{2}=4\] % error in R =% error in V+% error in I \[=\frac{0.5}{8}\times 100%+\frac{0.2}{2}\times 100%=16.25%\] \[R=4\Omega \pm 16.25%\]You need to login to perform this action.
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