A) 0.2Ma
B) 0.02mA
C) 0.5mA
D) 0.05mA
Correct Answer: A
Solution :
[a] The current voltage relation of diode is \[I=({{e}^{1000V/T}}-1)mA(given)\] When, \[I=5mA,{{e}^{1000V/T}}=6mA\] Also, \[dI=({{e}^{1000V/T}})\times \frac{1000}{T}\] (By exponential function) \[=(6mA)\times \frac{1000}{300}\times (0.01)=0.2mA\]You need to login to perform this action.
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