A) \[[M{{L}^{3}}]\]
B) \[[{{M}^{2}}L{{T}^{-5}}{{A}^{-2}}]\]
C) \[[{{M}^{2}}{{L}^{-3}}{{T}^{2}}{{A}^{-1}}]\]
D) \[[ML{{T}^{-2}}{{A}^{-2}}]\]
Correct Answer: B
Solution :
[b] \[[\overset{\to }{\mathop{E}}\,\times \overset{\to }{\mathop{B}}\,]=[\overset{\to }{\mathop{E]}}\,\times [B]\] \[[ML{{T}^{-3}}{{A}^{-1}}]\times [M{{L}^{-2}}{{A}^{-1}}]=[ML{{T}^{-5}}{{A}^{-2}}]\]
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