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JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Self Evaluation Test - Physical World, Units and Measurements

  • question_answer
    A quantity X is given by \[{{\varepsilon }_{0}}L\frac{\Delta V}{\Delta t}\] where \[{{\in }_{0}}\] is the permittivity of the free space, L is a length, \[\Delta V\]is a potential difference and \[\Delta t\] is a time interval. The dimensional formula for X is the same as that of        

    A)            Resistance 

    B)  charge

    C)  Voltage 

    D)  current

    Correct Answer: D

    Solution :

    [d] Dimensionally \[{{\varepsilon }_{0}}L=C\] where C= capacitance Now the given expression reduces to \[C\Delta V/\Delta t.\] Dimensionally \[C\Delta V=q\] where q is charge. Again the given expression reduces to \[q/\Delta t.\] Dimensionally\[\frac{q}{\Delta t}=I\] where I is current


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