A) \[m=\frac{c{{m}_{0}}}{\sqrt{1-{{v}^{2}}}}\]
B) \[m=\frac{{{m}_{0}}}{c\sqrt{1-{{v}^{2}}}}\]
C) \[m=\frac{{{m}_{0}}}{\sqrt{{{c}^{2}}-{{v}^{2}}}}\]
D) \[m=\frac{{{m}_{0}}}{\sqrt{1-\frac{{{v}^{2}}}{{{c}^{2}}}}}\]
Correct Answer: D
Solution :
[d] In, \[1-{{v}^{2}},{{v}^{2}}\]should be dimensionless, so it should be \[1-\frac{{{v}^{2}}}{{{c}^{2}}}\]
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