A) \[\frac{-3}{2},\frac{1}{2},1\]
B) \[-1,-2,3\]
C) \[\frac{1}{2},\,\frac{3}{2},\frac{1}{2}\]
D) \[1,\,2,\,\frac{1}{3}\]
Correct Answer: A
Solution :
[a] \[T={{[M{{L}^{-1}}{{T}^{-2}}]}^{a}}{{[{{L}^{-3}}M]}^{b}}{{[M{{T}^{-2}}]}^{c}}\] \[\Rightarrow b+a+c=0,-a-3b=0,-2a-2c=1\] \[\Rightarrow \,\,a=-\frac{3}{2},b=\frac{1}{2},c=1\]
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