A) \[ohm/{{m}^{2}}\]
B) \[ohm/{{m}^{3}}\]
C) \[ohm-m\]
D) \[ohm/m\]
Correct Answer: C
Solution :
[c] \[R=\rho \frac{l}{A}\,\,\therefore \,\,\rho =\frac{RA}{l}=\frac{\Omega {{m}^{2}}}{m}=\Omega m\]
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