A) \[dyne\times c{{m}^{5}}\]
B) \[dyne\times c{{m}^{4}}\]
C) \[dyne/c{{m}^{3}}\]
D) \[dyne\times c{{m}^{2}}\]
Correct Answer: B
Solution :
[b] As \[\frac{A}{{{V}^{2}}}=P\] \[\therefore \,\,a=P{{V}^{2}}=\frac{dyne}{c{{m}^{2}}}{{(c{{m}^{3}})}^{2}}=dyne\times c{{m}^{4}}\]
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