JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Self Evaluation Test - Physical World, Units and Measurements

  • question_answer
    The heat generated in a circuit is given by\[Q={{I}^{2}}Rt\], where I is current, R is resistance and t is time. If the percentage errors in measuring I, R and t are 2%, 1% and 1% respectively, then the maximum error in measuring heat will be

    A) 2%

    B)  3%  

    C)  4%

    D)  6%

    Correct Answer: D

    Solution :

    [d] \[\frac{\Delta Q}{Q}\times 100=\frac{2\Delta I}{I}\times 100+\frac{\Delta R}{R}\times 100+\frac{\Delta t}{t}\times 100\] \[=2\times 2%+1%+1%=6%\]


You need to login to perform this action.
You will be redirected in 3 sec spinner