JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Self Evaluation Test - Physical World, Units and Measurements

  • question_answer
    The resistance of a metal is given by \[R=\frac{V}{I}\]where V is potential difference and I is the current. In a circuit the potential difference across resistance is \[V=(8\pm 0.5)V\] and current in resistance \[I=(2\pm 0.2)A\]. What is the value of resistance with its percentage error?

    A) \[4\Omega \pm 16.25%\]

    B)  \[(4\pm 0.7)\Omega \]

    C)  \[4\Omega \pm 0.7%\]

    D)  \[4\Omega \pm 7%\]

    Correct Answer: A

    Solution :

    [a] Actual \[R=\frac{8}{2}=4\] % error in R =% error in V+% error in I  \[=\frac{0.5}{8}\times 100%+\frac{0.2}{2}\times 100%=16.25%\] \[R=4\Omega \pm 16.25%\]


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